A belt drive uses a 4-inch driver pulley to drive a 12-inch driven pulley. What is the speed ratio of driven to driver?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Prepare for the Valero Mechanical Aptitude Test with comprehensive study materials. Enhance your skills with flashcards, hints, and detailed explanations. Ace your exam with confidence!

Multiple Choice

A belt drive uses a 4-inch driver pulley to drive a 12-inch driven pulley. What is the speed ratio of driven to driver?

Explanation:
In a belt drive, the belt’s constant linear speed means the rotational speeds are inversely proportional to the pulley diameters: ω_driven/ω_driver = D_driver/D_driven. With a 4-inch driver and a 12-inch driven pulley, the driven speed is ω_driven = ω_driver × (4/12) = ω_driver/3. So the speed ratio (driven to driver) is 1/3, which is about 0.333.... This ratio makes sense: a much larger driven pulley rotates more slowly than the driver. If you had a driven pulley of 16 inches, the ratio would be 0.25; if it were 8 inches, the ratio would be 0.5; and if both pulleys were the same size, the ratio would be 1.

In a belt drive, the belt’s constant linear speed means the rotational speeds are inversely proportional to the pulley diameters: ω_driven/ω_driver = D_driver/D_driven. With a 4-inch driver and a 12-inch driven pulley, the driven speed is ω_driven = ω_driver × (4/12) = ω_driver/3. So the speed ratio (driven to driver) is 1/3, which is about 0.333....

This ratio makes sense: a much larger driven pulley rotates more slowly than the driver. If you had a driven pulley of 16 inches, the ratio would be 0.25; if it were 8 inches, the ratio would be 0.5; and if both pulleys were the same size, the ratio would be 1.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy