If three resistors of 6 Ω, 3 Ω, and 2 Ω are in a series circuit, their total resistance is

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Multiple Choice

If three resistors of 6 Ω, 3 Ω, and 2 Ω are in a series circuit, their total resistance is

Explanation:
In a series circuit, resistances simply add together because the same current flows through every resistor in line, so their effects stack to produce a larger overall resistance. Add the three values: 6 Ω + 3 Ω + 2 Ω equals 11 Ω. That total is what the source sees when all three resistors are connected in series. The other numbers would come from leaving out a resistor or counting only some of them, but with all three in series, you sum them all.

In a series circuit, resistances simply add together because the same current flows through every resistor in line, so their effects stack to produce a larger overall resistance. Add the three values: 6 Ω + 3 Ω + 2 Ω equals 11 Ω. That total is what the source sees when all three resistors are connected in series. The other numbers would come from leaving out a resistor or counting only some of them, but with all three in series, you sum them all.

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