In a hydraulic system, if the piston diameter remains constant and pressure increases, what happens to output force?

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Multiple Choice

In a hydraulic system, if the piston diameter remains constant and pressure increases, what happens to output force?

Explanation:
The main idea is that output force in a hydraulic cylinder depends on pressure times the piston area. With a fixed piston diameter, the cross-sectional area doesn’t change, so the force changes in direct proportion to pressure. In other words, F = P × A, and since A is constant, increasing P yields a proportional increase in F. This is a linear relationship, so doubling the pressure doubles the output force, not something exponential. The only way to get a non-proportional result would be if the area changed, which isn’t the case here.

The main idea is that output force in a hydraulic cylinder depends on pressure times the piston area. With a fixed piston diameter, the cross-sectional area doesn’t change, so the force changes in direct proportion to pressure. In other words, F = P × A, and since A is constant, increasing P yields a proportional increase in F. This is a linear relationship, so doubling the pressure doubles the output force, not something exponential. The only way to get a non-proportional result would be if the area changed, which isn’t the case here.

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