Two resistors, 6 Ω and 3 Ω, connected in parallel have an equivalent resistance of:

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Multiple Choice

Two resistors, 6 Ω and 3 Ω, connected in parallel have an equivalent resistance of:

Explanation:
In a parallel circuit, the total resistance is found by adding the reciprocals of each resistance: 1/Req = 1/R1 + 1/R2. With 6 Ω and 3 Ω, 1/Req = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2, so Req = 2 Ω. This matches the idea that the combined resistance in parallel is always less than the smallest individual resistor (here the smallest is 3 Ω), making 2 Ω a sensible result. The other numbers don’t fit the calculated reciprocal sum.

In a parallel circuit, the total resistance is found by adding the reciprocals of each resistance: 1/Req = 1/R1 + 1/R2. With 6 Ω and 3 Ω, 1/Req = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2, so Req = 2 Ω. This matches the idea that the combined resistance in parallel is always less than the smallest individual resistor (here the smallest is 3 Ω), making 2 Ω a sensible result. The other numbers don’t fit the calculated reciprocal sum.

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