What unit describes a hydraulic pump displacement per revolution, as used in the specification 100 in^3/rev?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Prepare for the Valero Mechanical Aptitude Test with comprehensive study materials. Enhance your skills with flashcards, hints, and detailed explanations. Ace your exam with confidence!

Multiple Choice

What unit describes a hydraulic pump displacement per revolution, as used in the specification 100 in^3/rev?

Explanation:
Displacement per revolution is the volume of fluid the pump moves with one full turn of the shaft. The specification 100 in^3/rev tells you that each revolution pushes 100 cubic inches of hydraulic fluid. That’s a volume-per-rotation unit, not a rate. The other units describe flow over time (per minute, per hour, per second), so they aren’t describing displacement per rotation. If you need to translate this into a flow rate, multiply by the shaft speed: GPM = (in^3 per rev × rpm) / 231, since 1 gallon = 231 cubic inches. For example, at 600 rpm, the flow would be about 600 × 100 / 231 ≈ 259 GPM.

Displacement per revolution is the volume of fluid the pump moves with one full turn of the shaft. The specification 100 in^3/rev tells you that each revolution pushes 100 cubic inches of hydraulic fluid. That’s a volume-per-rotation unit, not a rate.

The other units describe flow over time (per minute, per hour, per second), so they aren’t describing displacement per rotation. If you need to translate this into a flow rate, multiply by the shaft speed: GPM = (in^3 per rev × rpm) / 231, since 1 gallon = 231 cubic inches. For example, at 600 rpm, the flow would be about 600 × 100 / 231 ≈ 259 GPM.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy