Which equation expresses power in terms of current and resistance?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Prepare for the Valero Mechanical Aptitude Test with comprehensive study materials. Enhance your skills with flashcards, hints, and detailed explanations. Ace your exam with confidence!

Multiple Choice

Which equation expresses power in terms of current and resistance?

Explanation:
Power can be expressed in terms of current and resistance by combining the definitions of power and Ohm’s law. Start with the basic definition P = IV. Then use Ohm’s law V = IR to replace voltage with current times resistance. Substituting gives P = I(IR) = I^2 R. This form uses only current and resistance, giving the correct units for power (watts) because A^2·Ω = W. For example, if a current of 2 A flows through a 3 Ω resistor, the power dissipated is 2^2 × 3 = 12 W. Other forms like P = IV or P = V^2/R involve voltage, not solely current and resistance, and P = IR is not a valid expression for power.

Power can be expressed in terms of current and resistance by combining the definitions of power and Ohm’s law. Start with the basic definition P = IV. Then use Ohm’s law V = IR to replace voltage with current times resistance. Substituting gives P = I(IR) = I^2 R. This form uses only current and resistance, giving the correct units for power (watts) because A^2·Ω = W. For example, if a current of 2 A flows through a 3 Ω resistor, the power dissipated is 2^2 × 3 = 12 W. Other forms like P = IV or P = V^2/R involve voltage, not solely current and resistance, and P = IR is not a valid expression for power.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy